The number of water molecules present in $1.8\text{ g}$ of pure water is ($N_A = 6.022 \times 10^{23}\text{ mol}^{-1}$):
- A$6.022 \times 10^{22}$
- B$6.022 \times 10^{23}$
- C$3.011 \times 10^{22}$
- D$1.8 \times 10^{23}$
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