The magnetic field at the center of a circular loop of radius $R$ carrying steady current $I$ is $B_0$. At an axial distance $x = R$ from the center, the magnetic field is:
- A$B_0 / 2$
- B$B_0 / 4$
- C$B_0 / \sqrt{2}$
- D$B_0 / (2\sqrt{2})$
JEE (Main & Advanced) · Physics · Moving Charges and MagnetismMCQMedium
Practise JEE questions like this — with timed tests and instant analysis
Shared by Admin Test on EduBank. Free for students and teachers.
Start practising